Integrand size = 38, antiderivative size = 66 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-((b B+a C) x)-\frac {(b B+a C) \cot (c+d x)}{d}-\frac {a B \cot ^2(c+d x)}{2 d}-\frac {(a B-b C) \log (\sin (c+d x))}{d} \]
[Out]
Time = 0.21 (sec) , antiderivative size = 66, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.132, Rules used = {3713, 3672, 3610, 3612, 3556} \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {(a C+b B) \cot (c+d x)}{d}-\frac {(a B-b C) \log (\sin (c+d x))}{d}-x (a C+b B)-\frac {a B \cot ^2(c+d x)}{2 d} \]
[In]
[Out]
Rule 3556
Rule 3610
Rule 3612
Rule 3672
Rule 3713
Rubi steps \begin{align*} \text {integral}& = \int \cot ^3(c+d x) (a+b \tan (c+d x)) (B+C \tan (c+d x)) \, dx \\ & = -\frac {a B \cot ^2(c+d x)}{2 d}+\int \cot ^2(c+d x) (b B+a C-(a B-b C) \tan (c+d x)) \, dx \\ & = -\frac {(b B+a C) \cot (c+d x)}{d}-\frac {a B \cot ^2(c+d x)}{2 d}+\int \cot (c+d x) (-a B+b C-(b B+a C) \tan (c+d x)) \, dx \\ & = -((b B+a C) x)-\frac {(b B+a C) \cot (c+d x)}{d}-\frac {a B \cot ^2(c+d x)}{2 d}+(-a B+b C) \int \cot (c+d x) \, dx \\ & = -((b B+a C) x)-\frac {(b B+a C) \cot (c+d x)}{d}-\frac {a B \cot ^2(c+d x)}{2 d}-\frac {(a B-b C) \log (\sin (c+d x))}{d} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 3 in optimal.
Time = 0.51 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.17 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {a B \cot ^2(c+d x)+2 (b B+a C) \cot (c+d x) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},1,\frac {1}{2},-\tan ^2(c+d x)\right )+2 (a B-b C) (\log (\cos (c+d x))+\log (\tan (c+d x)))}{2 d} \]
[In]
[Out]
Time = 0.34 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.17
method | result | size |
derivativedivides | \(\frac {B b \left (-\cot \left (d x +c \right )-d x -c \right )+C b \ln \left (\sin \left (d x +c \right )\right )+B a \left (-\frac {\cot \left (d x +c \right )^{2}}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+C a \left (-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(77\) |
default | \(\frac {B b \left (-\cot \left (d x +c \right )-d x -c \right )+C b \ln \left (\sin \left (d x +c \right )\right )+B a \left (-\frac {\cot \left (d x +c \right )^{2}}{2}-\ln \left (\sin \left (d x +c \right )\right )\right )+C a \left (-\cot \left (d x +c \right )-d x -c \right )}{d}\) | \(77\) |
parallelrisch | \(\frac {-B a \cot \left (d x +c \right )^{2}-2 B b d x -2 C a d x -2 B b \cot \left (d x +c \right )-2 B a \ln \left (\tan \left (d x +c \right )\right )+B \ln \left (\sec \left (d x +c \right )^{2}\right ) a -2 C a \cot \left (d x +c \right )+2 C \ln \left (\tan \left (d x +c \right )\right ) b -C \ln \left (\sec \left (d x +c \right )^{2}\right ) b}{2 d}\) | \(98\) |
norman | \(\frac {\left (-B b -C a \right ) x \tan \left (d x +c \right )^{3}-\frac {\left (B b +C a \right ) \tan \left (d x +c \right )^{2}}{d}-\frac {B a \tan \left (d x +c \right )}{2 d}}{\tan \left (d x +c \right )^{3}}-\frac {\left (B a -C b \right ) \ln \left (\tan \left (d x +c \right )\right )}{d}+\frac {\left (B a -C b \right ) \ln \left (1+\tan \left (d x +c \right )^{2}\right )}{2 d}\) | \(108\) |
risch | \(-B b x -C a x +i B a x -i C b x +\frac {2 i B a c}{d}-\frac {2 i C b c}{d}-\frac {2 i \left (i B a \,{\mathrm e}^{2 i \left (d x +c \right )}+B b \,{\mathrm e}^{2 i \left (d x +c \right )}+C a \,{\mathrm e}^{2 i \left (d x +c \right )}-B b -C a \right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{2}}-\frac {B a \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d}+\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) C b}{d}\) | \(145\) |
[In]
[Out]
none
Time = 0.24 (sec) , antiderivative size = 95, normalized size of antiderivative = 1.44 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {{\left (B a - C b\right )} \log \left (\frac {\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{2} + {\left (2 \, {\left (C a + B b\right )} d x + B a\right )} \tan \left (d x + c\right )^{2} + B a + 2 \, {\left (C a + B b\right )} \tan \left (d x + c\right )}{2 \, d \tan \left (d x + c\right )^{2}} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 143 vs. \(2 (56) = 112\).
Time = 1.07 (sec) , antiderivative size = 143, normalized size of antiderivative = 2.17 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=\begin {cases} \text {NaN} & \text {for}\: c = 0 \wedge d = 0 \\x \left (a + b \tan {\left (c \right )}\right ) \left (B \tan {\left (c \right )} + C \tan ^{2}{\left (c \right )}\right ) \cot ^{4}{\left (c \right )} & \text {for}\: d = 0 \\\text {NaN} & \text {for}\: c = - d x \\\frac {B a \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} - \frac {B a \log {\left (\tan {\left (c + d x \right )} \right )}}{d} - \frac {B a}{2 d \tan ^{2}{\left (c + d x \right )}} - B b x - \frac {B b}{d \tan {\left (c + d x \right )}} - C a x - \frac {C a}{d \tan {\left (c + d x \right )}} - \frac {C b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 d} + \frac {C b \log {\left (\tan {\left (c + d x \right )} \right )}}{d} & \text {otherwise} \end {cases} \]
[In]
[Out]
none
Time = 0.32 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.30 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {2 \, {\left (C a + B b\right )} {\left (d x + c\right )} - {\left (B a - C b\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) + 2 \, {\left (B a - C b\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac {B a + 2 \, {\left (C a + B b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{2}}}{2 \, d} \]
[In]
[Out]
Leaf count of result is larger than twice the leaf count of optimal. 179 vs. \(2 (64) = 128\).
Time = 1.31 (sec) , antiderivative size = 179, normalized size of antiderivative = 2.71 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {B a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 \, C a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 4 \, B b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 8 \, {\left (C a + B b\right )} {\left (d x + c\right )} - 8 \, {\left (B a - C b\right )} \log \left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right ) + 8 \, {\left (B a - C b\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) \right |}\right ) - \frac {12 \, B a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 12 \, C b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 4 \, C a \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 4 \, B b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - B a}{\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2}}}{8 \, d} \]
[In]
[Out]
Time = 7.98 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.64 \[ \int \cot ^4(c+d x) (a+b \tan (c+d x)) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx=-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,\left (B\,a-C\,b\right )}{d}-\frac {{\mathrm {cot}\left (c+d\,x\right )}^2\,\left (\frac {B\,a}{2}+\mathrm {tan}\left (c+d\,x\right )\,\left (B\,b+C\,a\right )\right )}{d}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )\,\left (B+C\,1{}\mathrm {i}\right )\,\left (a+b\,1{}\mathrm {i}\right )}{2\,d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )\,\left (B-C\,1{}\mathrm {i}\right )\,\left (b+a\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2\,d} \]
[In]
[Out]